Originally Posted by
Uhhwat
〖64〗_(n=) (64(〖48〗_1+〖426〗_n))/2=15,168
I had to go into word for this but, its arithmetic sequence i have to find the sum of 64 terms so i put 64 over n equals to 64 times 48 plus 426 dived by 2 which equals to 15,168. I first added 48 and 426 together then i got 474. 474 times 64 equals to 30,336. Half of that is 15,168
Also sorry i dont know how to paste my equation from word exactly like it is to here
Yes, this is the correct result.
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Also for those who still confused with his equation, there are simple manner.
First of all, we've to find determinant of Term/I.
I = a + (n - 1) x d
=48 + (64 - 1) x 6
=426
Next, integrate the result and multiply them with
last equation.
s = n/2 (a + I)
=64/2 (48 + 426)
=15, 168
Originally Posted by
SkilleXGaming
S*64=64/2(6+384)=15168
I think that is right. Right?
Sorry.
His answer and equation are most accurate.
Moreover he was answer first correctly (check previous page).
Last edited by KinezIvan; Jun 25, 2014 at 03:24 AM.